<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-5751395376029001098</id><updated>2012-02-16T06:11:35.637-08:00</updated><title type='text'>CADA DOS DIAS UN PROBLEMA</title><subtitle type='html'>Cada dos dias se publicara en este lugar un problema.

Puedes escribir tus solucioens y comentarios en el blog.

También puedes enviar tu solución a abueno34@gmail.com</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>51</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-1543559643118373400</id><published>2012-01-22T10:17:00.000-08:00</published><updated>2012-01-22T10:32:30.818-08:00</updated><title type='text'>El precio de los sombreros.</title><content type='html'>En una tienda sombreros tenían un sobrero de copa marcado con un precio de 25 €. Pasado un mes, el sombrero no se había vendido, por lo que fue rebajado, pasando a costar 10 €.&lt;br /&gt;Un mes más tarde, visto que nadie compraba el sombrero, volvieron a rebajarlo, costando entonces 4 €.&lt;br /&gt;Un mes después lo pusieron a 1.60 €, esperando poderlo vender, porque si volvieran a rebajarlo, siguiendo la secuencia de rebajas aplicado hasta ahora, el precio resultante sería menor que el precio de coste. ¿Cuál será el precio de una nueva rebaja?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-1543559643118373400?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/1543559643118373400/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=1543559643118373400' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1543559643118373400'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1543559643118373400'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2012/01/el-precio-de-los-sombreros.html' title='El precio de los sombreros.'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2606882042595426267</id><published>2011-04-18T05:10:00.000-07:00</published><updated>2011-04-18T05:53:41.055-07:00</updated><title type='text'>Las bolas de hierro.</title><content type='html'>Tenemos dos cajas con forma de cubo con las mismas dimensiones.&lt;br /&gt;&lt;br /&gt;Una contiene una esfera de hierro con un diámetro igual a la arista del cubo.&lt;br /&gt;&lt;br /&gt;La otra está llena de pequeñas esferas de hierro encajadas tal como se ve en la imagen.&lt;br /&gt;&lt;br /&gt;¿Qué caja pesa más?&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/-8IJtWd97w1E/Taw0OZTQHAI/AAAAAAAAAEM/gmsLae_S96k/s1600/bolas.jpg"&gt;&lt;img style="display: block; margin: 0px auto 10px; text-align: center; cursor: pointer; width: 320px; height: 154px;" src="http://4.bp.blogspot.com/-8IJtWd97w1E/Taw0OZTQHAI/AAAAAAAAAEM/gmsLae_S96k/s320/bolas.jpg" alt="" id="BLOGGER_PHOTO_ID_5596905858829130754" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2606882042595426267?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2606882042595426267/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2606882042595426267' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2606882042595426267'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2606882042595426267'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2011/04/las-bolas-de-hierro.html' title='Las bolas de hierro.'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/-8IJtWd97w1E/Taw0OZTQHAI/AAAAAAAAAEM/gmsLae_S96k/s72-c/bolas.jpg' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4297768853786826951</id><published>2011-01-04T03:06:00.000-08:00</published><updated>2011-01-04T03:08:50.855-08:00</updated><title type='text'>Seis dígitos...</title><content type='html'>Elige seis dígitos y forma con ellos dos números, usando cada dígito una sola vez. Busca la combinación más adecuada para obtener el mayor producto posible. Y también el menor.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4297768853786826951?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4297768853786826951/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4297768853786826951' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4297768853786826951'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4297768853786826951'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2011/01/seis-digitos.html' title='Seis dígitos...'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-3188342772347255917</id><published>2010-12-23T11:49:00.000-08:00</published><updated>2010-12-23T11:59:54.584-08:00</updated><title type='text'>Equis y Oes</title><content type='html'>Escribimos nueve letras, entre equis y oes, formando el siguiente texto:&lt;br /&gt;&lt;br /&gt;&lt;div style="text-align: center; color: rgb(255, 0, 0); font-weight: bold;"&gt;&lt;span style="font-size:180%;"&gt;XOXOOXXOO&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;&lt;br /&gt;Podemos eliminar letras contiguas, tomándolas de dos en dos, y sustituyando cada par eliminado de la forma siguiente:&lt;br /&gt;&lt;ul&gt;&lt;li&gt;&lt;span style="font-size:100%;"&gt;Dos letras iguales pueden cambiarse por una...  &lt;/span&gt;&lt;span style="color: rgb(255, 0, 0); font-weight: bold;font-size:100%;" &gt;O&lt;/span&gt;&lt;/li&gt;&lt;li&gt;&lt;span style="color: rgb(255, 0, 0);font-size:100%;" &gt;&lt;span style="color: rgb(0, 0, 0);"&gt;Dos letras distintas pueden cambiarse por una... &lt;span style="color: rgb(255, 0, 0);"&gt;&lt;span style="font-weight: bold;"&gt;X&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/span&gt;&lt;/li&gt;&lt;/ul&gt;&lt;span style="font-size:100%;"&gt;¿Es posible eliminar las letras para que al final quede una &lt;/span&gt;&lt;span style="color: rgb(255, 0, 0);font-size:100%;" &gt;&lt;span style="font-weight: bold;"&gt;X&lt;/span&gt;&lt;/span&gt;&lt;span style="font-size:100%;"&gt;?&lt;/span&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;Prueba cambiando la disposición inicial de equis y de oes.&lt;br /&gt;&lt;/li&gt;&lt;li&gt;Prueba cambiando el número y la disposición inicial de equis y de oes.&lt;/li&gt;&lt;/ul&gt;¿A qué conclusión te llevan estos cambios?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-3188342772347255917?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/3188342772347255917/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=3188342772347255917' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/3188342772347255917'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/3188342772347255917'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/12/equis-y-oes.html' title='Equis y Oes'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8427416759886787762</id><published>2010-12-14T16:27:00.000-08:00</published><updated>2010-12-14T16:32:44.065-08:00</updated><title type='text'>Las citys del desierto</title><content type='html'>Las carreteras que atraviesan los desiertos, si las dunas lo permiten, acostumbran a ser muy, pero que muy, rectas. En el desierto del Gobi hay una carretera que une, por orden, cuatro ciudades: Firstcity, Secondcity, Thirdcity y Fourcity.&lt;br /&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;Thirdcity está a 60 km de Firstcity&lt;/li&gt;&lt;li&gt;      Fourcity está a 40 km de Secondcity&lt;/li&gt;&lt;li&gt;Thirdcity está 10 km más cerca de Fourcity que de Secondcity&lt;/li&gt;&lt;/ul&gt;&lt;br /&gt;¿Qué distancia hay entre Firstcity y Fourcity?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8427416759886787762?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8427416759886787762/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8427416759886787762' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8427416759886787762'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8427416759886787762'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/12/las-citys-del-desierto.html' title='Las citys del desierto'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4005154239842713240</id><published>2010-12-12T04:21:00.000-08:00</published><updated>2010-12-12T04:24:07.481-08:00</updated><title type='text'>Curioso 45</title><content type='html'>El 45 es un número muy curioso. Si lo elevamos al cuadrado obtenemos 45*45 = 2025. Si ahora cogemos el 2025 y lo cortamos en dos mitades (20 y 25) y las sumamos volvemos a tener el 45. (20+25=45)&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Entre 10 y 100 sólo hay dos números más que tengan la misma propiedad. ¿Cuáles son?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4005154239842713240?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4005154239842713240/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4005154239842713240' title='4 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4005154239842713240'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4005154239842713240'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/12/curioso-45.html' title='Curioso 45'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-1034339539912091591</id><published>2010-12-10T00:33:00.000-08:00</published><updated>2010-12-10T00:36:29.664-08:00</updated><title type='text'>Más parejas...</title><content type='html'>Un día en clase de matemáticas el maestro hizo notar que&lt;br /&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;2 + 2 = 4&lt;/li&gt;&lt;li&gt;2 . 2 = 4&lt;br /&gt;&lt;/li&gt;&lt;/ul&gt;&lt;br /&gt;El 2 es el único número natural que cumple esta propiedad. Pero si no imponemos que los números que sumamos sean iguales seguro que, con fracciones u otros&lt;br /&gt;tipos de números, podemos encontrar otras parejas de números que cumplan que&lt;br /&gt;a+b = a · b&lt;br /&gt;&lt;br /&gt;¿Podrias encontrar alguna pareja de números que cumplan la condición?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-1034339539912091591?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/1034339539912091591/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=1034339539912091591' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1034339539912091591'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1034339539912091591'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/12/mas-parejas.html' title='Más parejas...'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6824157274378330880</id><published>2010-12-03T00:28:00.000-08:00</published><updated>2010-12-03T00:34:44.801-08:00</updated><title type='text'>Memoria telefónica</title><content type='html'>Mi cuñada Ana recuerda los seis últimos dígitos del teléfono de su amiga Sole porque el primero es un 1, y porque si  pone el 1 del comienzo al final y deja el resto de números en el mismo orden, el número queda automáticamente multiplicado por 3.&lt;br /&gt;&lt;br /&gt;¿Cuáles son los seis últimos dígitos del número de Sole&lt;span class="unknown"&gt;&lt;/span&gt;?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6824157274378330880?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6824157274378330880/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6824157274378330880' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6824157274378330880'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6824157274378330880'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/12/memoria-telefonica.html' title='Memoria telefónica'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6796712753252443620</id><published>2010-11-26T00:13:00.000-08:00</published><updated>2010-11-26T00:17:46.602-08:00</updated><title type='text'>¿Sopa de letras?</title><content type='html'>﻿En el &lt;span class="alternative"&gt;tablero&lt;/span&gt; de letras puedes ver las cinco vocales repetidas cinco veces cada una. ¿Podrías dividir el tablero en cinco partes de manera que cada una contenga las cinco vocales (a, &lt;span class="unknown"&gt;e&lt;/span&gt;, i, &lt;span class="unknown"&gt;o&lt;/span&gt;, u).&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_IdKVSMTg8EI/TO9s9pSMqQI/AAAAAAAAAD8/Osiuqwh45tM/s1600/letras.jpg"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 165px; height: 169px;" src="http://4.bp.blogspot.com/_IdKVSMTg8EI/TO9s9pSMqQI/AAAAAAAAAD8/Osiuqwh45tM/s320/letras.jpg" alt="" id="BLOGGER_PHOTO_ID_5543769472626370818" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6796712753252443620?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6796712753252443620/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6796712753252443620' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6796712753252443620'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6796712753252443620'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/11/sopa-de-letras.html' title='¿Sopa de letras?'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_IdKVSMTg8EI/TO9s9pSMqQI/AAAAAAAAAD8/Osiuqwh45tM/s72-c/letras.jpg' height='72' width='72'/><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-663347405703812121</id><published>2010-11-16T07:24:00.001-08:00</published><updated>2010-11-16T07:24:50.207-08:00</updated><title type='text'>Uno de edades...</title><content type='html'>&lt;ul&gt;&lt;li&gt;Dígame abuelo... Qué edad tiene su hija?&lt;/li&gt;&lt;li&gt;Tiene tantas semanas como días tiene mi nieta.&lt;/li&gt;&lt;li&gt;Y qué edad tiene su nieta?&lt;/li&gt;&lt;li&gt;Tiene tantos meses como años tengo yo.&lt;/li&gt;&lt;li&gt;Entonces... Qué edad tiene usted?&lt;/li&gt;&lt;li&gt;Los tres juntos tenemos exactamente 100 años.&lt;br /&gt;&lt;/li&gt;&lt;/ul&gt;Cuál es la edad de cada cual?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-663347405703812121?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/663347405703812121/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=663347405703812121' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/663347405703812121'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/663347405703812121'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/11/uno-de-edades.html' title='Uno de edades...'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8986947765600294079</id><published>2010-10-17T09:22:00.000-07:00</published><updated>2010-10-17T09:24:01.400-07:00</updated><title type='text'>Pesadas</title><content type='html'>Un tendero dispone de una balanza y 4 pesas: una de 1 kg, otra de 3 kg, una de 9 kg y la última de 27 kg.&lt;br /&gt;&lt;br /&gt;Disponiéndolas convenientemente en los platos de la balanza consigue hacer cualquier pesada entera entre 1 y 40 kg.&lt;br /&gt;&lt;br /&gt;¿Qué combinación de pesas debe hacer para cada pesada?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8986947765600294079?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8986947765600294079/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8986947765600294079' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8986947765600294079'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8986947765600294079'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/10/pesadas.html' title='Pesadas'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4966927190830304194</id><published>2010-10-10T10:35:00.000-07:00</published><updated>2010-10-10T10:43:59.065-07:00</updated><title type='text'>El problema de Tartaglia</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_IdKVSMTg8EI/TLH7SquK7cI/AAAAAAAAADs/1T_TDYBWMBU/s1600/24.jpg"&gt;&lt;img style="float: right; margin: 0pt 0pt 10px 10px; cursor: pointer; width: 114px; height: 173px;" src="http://4.bp.blogspot.com/_IdKVSMTg8EI/TLH7SquK7cI/AAAAAAAAADs/1T_TDYBWMBU/s320/24.jpg" alt="" id="BLOGGER_PHOTO_ID_5526474515884469698" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;De qué modo podrías dividir el contenido de una jarra de 24 litros en tres partes iguales, utilizando solamente la jarra original y otras tres de 5, 11 y 13 litros respectivamente.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4966927190830304194?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4966927190830304194/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4966927190830304194' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4966927190830304194'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4966927190830304194'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/10/el-problema-de-tartaglia.html' title='El problema de Tartaglia'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_IdKVSMTg8EI/TLH7SquK7cI/AAAAAAAAADs/1T_TDYBWMBU/s72-c/24.jpg' height='72' width='72'/><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8341588571407670715</id><published>2010-09-30T08:51:00.000-07:00</published><updated>2010-09-30T08:52:48.389-07:00</updated><title type='text'>Elisabeth goes for a walk</title><content type='html'>Elizabeth visits her friend Andrew and then returns home by the same  route.  She always walks 2km/h when going uphill, 6km/h when going downhill  and 3km/h when on level ground.  If her total walking time is 6 hours, then  what is the total distance she walks in km?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8341588571407670715?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8341588571407670715/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8341588571407670715' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8341588571407670715'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8341588571407670715'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/09/elisabeth-goes-for-walk.html' title='Elisabeth goes for a walk'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-5342366137058573029</id><published>2010-09-27T10:04:00.000-07:00</published><updated>2010-09-27T10:12:23.011-07:00</updated><title type='text'>El perro y el conejo (The dog and the rabbit)</title><content type='html'>&lt;b style="font-family: times new roman;"&gt;Un perro que persigue un conejo avanza 3m con cada zancada. El conejo  por su parte avanza con saltos de 2m. ¿En cuántos zancadas alcanzará el  perro al conejo si éste tenía una ventaja de &lt;/b&gt;&lt;b style="font-family: times new roman;"&gt;45m?&lt;/b&gt;&lt;b style="font-family: times new roman;"&gt;&lt;/b&gt;&lt;b style="font-family: times new roman;"&gt;&lt;br /&gt;&lt;br /&gt;&lt;/b&gt;&lt;div style="text-align: center; font-family: times new roman;"&gt;&lt;b&gt;_____________________________&lt;/b&gt;&lt;br /&gt;&lt;/div&gt;&lt;b style="font-family: times new roman;"&gt;&lt;br /&gt;&lt;/b&gt;&lt;b style="font-family: times new roman;"&gt;A dog chasing a rabbit, which has a start of 45m, jumps 3m every time the rabbit jumps 2m. In how many leaps does the dog overtake the rabbit?&lt;/b&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-5342366137058573029?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/5342366137058573029/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=5342366137058573029' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5342366137058573029'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5342366137058573029'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/09/el-perro-y-el-conejo-dog-and-rabbit.html' title='El perro y el conejo (The dog and the rabbit)'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4305490726148656218</id><published>2010-08-17T04:51:00.000-07:00</published><updated>2010-08-17T04:55:56.267-07:00</updated><title type='text'>Triágulos</title><content type='html'>Dado un triángulo equilátero, cuyos vértices son tres puntos llamados A, B y C; sean D, E y F respectivemente los puntos medios de BC, CA y AB; y sean P, Q y R respectivamente los puntos medios de AF, BD y CE.&lt;br /&gt;&lt;br /&gt;Los segmentos DP, EQ y FR se cortan formando un nuevo triángulo.&lt;br /&gt;&lt;br /&gt;¿Cuál es la relación entre el valor del área del triángulo formado y del triángulo equilátero original?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4305490726148656218?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4305490726148656218/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4305490726148656218' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4305490726148656218'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4305490726148656218'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/08/triagulos.html' title='Triágulos'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4195471590083159228</id><published>2010-05-23T15:11:00.000-07:00</published><updated>2010-05-23T15:13:25.223-07:00</updated><title type='text'>Múltiplo de tres</title><content type='html'>Demostrar que el número siguiente al que resulta de sumar los cuadrados de tres números naturales consecutivos es múltiplo de 3.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4195471590083159228?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4195471590083159228/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4195471590083159228' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4195471590083159228'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4195471590083159228'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/05/multiplo-de-tres.html' title='Múltiplo de tres'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-3421010397176756387</id><published>2010-05-19T04:19:00.001-07:00</published><updated>2010-05-23T15:59:00.295-07:00</updated><title type='text'>Seis monedas</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_IdKVSMTg8EI/S_PKBH9DOjI/AAAAAAAAADc/PzvsG_832Ok/s1600/monedas.JPG"&gt;&lt;img style="float: right; margin: 0pt 0pt 10px 10px; cursor: pointer; width: 320px; height: 99px;" src="http://1.bp.blogspot.com/_IdKVSMTg8EI/S_PKBH9DOjI/AAAAAAAAADc/PzvsG_832Ok/s320/monedas.JPG" alt="" id="BLOGGER_PHOTO_ID_5472940092849076786" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Tenemos 6 monedas que forman un paralelogramo y  debemos ponerlas  formando un círculo, moviendo cada vez una moneda. Pero cada vez que  movemos una se debe  dejar de  manera que su contorno toque el contorno de otras dos monedas. ¿Cómo resolverías el juego con sólo tres movimientos?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-3421010397176756387?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/3421010397176756387/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=3421010397176756387' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/3421010397176756387'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/3421010397176756387'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/05/tenemos-6-monedas-que-forman-un.html' title='Seis monedas'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_IdKVSMTg8EI/S_PKBH9DOjI/AAAAAAAAADc/PzvsG_832Ok/s72-c/monedas.JPG' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-5649482800222168493</id><published>2010-05-03T08:13:00.000-07:00</published><updated>2010-05-23T15:59:44.429-07:00</updated><title type='text'>Liberad a Robín</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_IdKVSMTg8EI/S99M5Dv2ArI/AAAAAAAAADU/muMe4sfJBFI/s1600/gato01.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 198px; height: 200px;" src="http://4.bp.blogspot.com/_IdKVSMTg8EI/S99M5Dv2ArI/AAAAAAAAADU/muMe4sfJBFI/s200/gato01.jpg" alt="" id="BLOGGER_PHOTO_ID_5467173015793304242" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Un malvado secuestró a mi gato "Robín", y lo ha colocado, con las patas bien atadas para que no pueda saltar, en una plataforma cuadrada, rodeada por un foso lleno de agua con 20 m de profundidad y 3m de anchura.&lt;br /&gt;&lt;br /&gt;Para liberar a "Robín" sólo tenemos un par de tablones de madera de 2,99 m de longitud y 10 cm de anchura.&lt;br /&gt;&lt;br /&gt;No tenemos ni clavos, ni martillos... Tampoco puedo saltar usando el tablón a modo de pértiga, porque tengo un tobillo algo lesionado.&lt;br /&gt;&lt;br /&gt;¿Qué puedo hacer para entrar y salir de la plataforma?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-5649482800222168493?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/5649482800222168493/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=5649482800222168493' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5649482800222168493'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5649482800222168493'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/05/liberar-robin.html' title='Liberad a Robín'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_IdKVSMTg8EI/S99M5Dv2ArI/AAAAAAAAADU/muMe4sfJBFI/s72-c/gato01.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8397302609440329326</id><published>2010-04-23T08:32:00.000-07:00</published><updated>2010-04-23T08:36:10.569-07:00</updated><title type='text'>El reparto del vino</title><content type='html'>Dos chicos tienen una garrafa con 8 litros de vino de La Roda&lt;span class="unknown"&gt;&lt;/span&gt; y se lo quieren repartir, como dos buenos amigos, a partes iguales. Pero para medir sólo disponen de un par de &lt;span class="unknown"&gt;garrafas&lt;/span&gt; vacías de 5 y 3 litros respectivamente.&lt;br /&gt;¿Cómo podrán hacer el reparto? (No vale hacer medidas "a ojo" como la mitad de la garrafa)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8397302609440329326?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8397302609440329326/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8397302609440329326' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8397302609440329326'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8397302609440329326'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/04/el-reparto-del-vino.html' title='El reparto del vino'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8113249363282858664</id><published>2010-04-21T14:23:00.000-07:00</published><updated>2010-04-21T14:24:20.426-07:00</updated><title type='text'>La cerca del jardín</title><content type='html'>Un jardín rectangular que tiene dimensiones 50 metros de largo por 10 metros de ancho está encerrado con una cerca de madera. Para hacer un jardín más grande, se usa la misma cerca para encerrar un terreno cuadrado. ¿Cuál es el diferencia, en metros cuadrados, entre el área del jardín rectangular y el jardín cuadrado?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8113249363282858664?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8113249363282858664/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8113249363282858664' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8113249363282858664'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8113249363282858664'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/04/la-cerca-del-jardin.html' title='La cerca del jardín'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2310005341117213628</id><published>2010-04-06T05:15:00.000-07:00</published><updated>2010-04-06T06:34:42.345-07:00</updated><title type='text'>Las ruedas de Juan Frenando</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_IdKVSMTg8EI/S7srryverII/AAAAAAAAADE/znVwBI_FOJk/s1600/23752__10_a_1.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 164px;" src="http://3.bp.blogspot.com/_IdKVSMTg8EI/S7srryverII/AAAAAAAAADE/znVwBI_FOJk/s200/23752__10_a_1.jpg" alt="" id="BLOGGER_PHOTO_ID_5457003404844772482" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Don Juan Frenando tiene que hacer un viaje de 42000 km.&lt;br /&gt;Las ruedas que utiliza aguantan, como mucho, 24000 km. Por lo tanto parece que le hacen falta 8&lt;br /&gt;ruedas para poder hacer todo el viaje (4 para los 24000 primeros y otros 4 para los 18000 restantes)&lt;br /&gt;&lt;br /&gt;Él, sin embargo, dice que, si hace intercambios adecuados entre ellas, puede hacerlo sólo con 7 ruedas.&lt;br /&gt;&lt;br /&gt;¿Tiene razón Don Juan Frenando? ¿Si tiene, cómo lo hará?&lt;br /&gt;&lt;br /&gt;&lt;span style="font-size:85%;"&gt;&lt;br /&gt;Imagen obtenida bajo licencia CC: &lt;a href="http://bancoimagenes.isftic.mepsyd.es/"&gt;Banco de imágenes y sonidos del ITE&lt;/a&gt;&lt;/span&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2310005341117213628?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2310005341117213628/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2310005341117213628' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2310005341117213628'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2310005341117213628'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/04/las-ruedas-de-juan-frenando.html' title='Las ruedas de Juan Frenando'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_IdKVSMTg8EI/S7srryverII/AAAAAAAAADE/znVwBI_FOJk/s72-c/23752__10_a_1.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-5244054878389215745</id><published>2010-01-08T03:13:00.000-08:00</published><updated>2010-01-08T03:14:05.837-08:00</updated><title type='text'>Comienza de nuevo esta actividad</title><content type='html'>Estimados alumnos de ESO y Bachillerato... este blog volverá a estar activo en breve.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-5244054878389215745?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/5244054878389215745/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=5244054878389215745' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5244054878389215745'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5244054878389215745'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2010/01/comienza-de-nuevo-esta-actividad.html' title='Comienza de nuevo esta actividad'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-113425801709688800</id><published>2009-02-08T02:24:00.000-08:00</published><updated>2009-02-08T02:28:48.780-08:00</updated><title type='text'>PELOS</title><content type='html'>Se ha contado que, por término medio, en la cabeza humana hay 150.000 pelos. También se ha determinado que, mensualmente se caen unos 3000.&lt;br /&gt;¿Cuánto tiempo, por término medio, dura un pelo en la cabeza?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-113425801709688800?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/113425801709688800/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=113425801709688800' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/113425801709688800'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/113425801709688800'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/02/pelos.html' title='PELOS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-5543959809999368600</id><published>2009-02-06T00:49:00.000-08:00</published><updated>2009-02-06T00:53:37.089-08:00</updated><title type='text'>POLÍGONOS EN CAJAS</title><content type='html'>Sobre una mesa hay tres cajas, y dentro de cada una de ellas un polígono regular, cumpliéndose las condiciones siguientes:&lt;br /&gt;&lt;br /&gt;&lt;ul&gt;&lt;li&gt;El polígono de la primera caja tiene el doble de vértices que el de la segunda caja.&lt;/li&gt;&lt;li&gt;El polígono de la caja tercera tiene un lado más que el de la segunda caja y dos lados menos que el de la primera.&lt;br /&gt;&lt;/li&gt;&lt;/ul&gt;&lt;br /&gt;¿Qué polígono contiene cada una de las cajas?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-5543959809999368600?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/5543959809999368600/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=5543959809999368600' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5543959809999368600'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5543959809999368600'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/02/poligonos-en-cajas.html' title='POLÍGONOS EN CAJAS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8082506707000885710</id><published>2009-02-06T00:48:00.001-08:00</published><updated>2009-02-06T00:48:52.258-08:00</updated><title type='text'>COLOCANDO BOTONES</title><content type='html'>Se colocan unos botones de la siguiente manera: 1 rojo, 1 verde, 3 rojos, 3 verdes, 5 rojos, 5 verdes,  aumentando de dos en dos el número de botones.&lt;br /&gt;&lt;br /&gt;¿Cuántos botones rojos hay entre los primeros 100 botones colocado?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8082506707000885710?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8082506707000885710/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8082506707000885710' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8082506707000885710'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8082506707000885710'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/02/colocando-botones.html' title='COLOCANDO BOTONES'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2989092257478714086</id><published>2009-01-31T15:28:00.000-08:00</published><updated>2009-01-31T15:33:52.773-08:00</updated><title type='text'>CUADRADOS</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_IdKVSMTg8EI/SYTfgyKLbkI/AAAAAAAAACM/YZm2gDcS9mc/s1600-h/cuadrados.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 129px; height: 130px;" src="http://1.bp.blogspot.com/_IdKVSMTg8EI/SYTfgyKLbkI/AAAAAAAAACM/YZm2gDcS9mc/s320/cuadrados.jpg" alt="" id="BLOGGER_PHOTO_ID_5297604816007818818" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;En la imagen puedes ver cuadrados de diferentes medidas, ¿podrías indicar cuántos?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2989092257478714086?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2989092257478714086/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2989092257478714086' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2989092257478714086'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2989092257478714086'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/cuadrados.html' title='CUADRADOS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_IdKVSMTg8EI/SYTfgyKLbkI/AAAAAAAAACM/YZm2gDcS9mc/s72-c/cuadrados.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2219608299771200658</id><published>2009-01-31T15:23:00.000-08:00</published><updated>2009-01-31T15:27:51.036-08:00</updated><title type='text'>FRUTAS MATEMÁTICAS</title><content type='html'>Tres manzanas y una pera pesan lo mismo que diez albaricoques. Una pera pesa lo mismo que seis albaricoques y una manzana. ¿Cuántas menzanas pesa cada pera?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2219608299771200658?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2219608299771200658/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2219608299771200658' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2219608299771200658'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2219608299771200658'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/frutas-matematicas.html' title='FRUTAS MATEMÁTICAS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2088788299004409925</id><published>2009-01-27T15:02:00.001-08:00</published><updated>2009-01-27T15:02:43.415-08:00</updated><title type='text'>LA FAMILIA MATA</title><content type='html'>A la familia Mata le ocurre una cosa bien curiosa. Cada chica tiene tantos hermanos como hermanas y cada chico tiene el doble de hermanas que de hermanos. ¿Cuántas chicas y cuántos chicos forman la familia?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2088788299004409925?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2088788299004409925/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2088788299004409925' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2088788299004409925'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2088788299004409925'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/la-familia-mata.html' title='LA FAMILIA MATA'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4579866510146301540</id><published>2009-01-25T03:31:00.000-08:00</published><updated>2009-01-25T03:32:15.907-08:00</updated><title type='text'>EL TRONCO</title><content type='html'>¿Qué altura tiene un tronco que es dos metros más corto que un árbol de altura triple que la del tronco?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4579866510146301540?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4579866510146301540/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4579866510146301540' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4579866510146301540'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4579866510146301540'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/el-tronco.html' title='EL TRONCO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2580129926531838963</id><published>2009-01-22T15:11:00.000-08:00</published><updated>2009-01-22T15:16:13.182-08:00</updated><title type='text'>TIRA A LA DIANA</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_IdKVSMTg8EI/SXj-Oeeb7QI/AAAAAAAAACE/AG-nIDKCFL8/s1600-h/diana.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 197px; height: 188px;" src="http://3.bp.blogspot.com/_IdKVSMTg8EI/SXj-Oeeb7QI/AAAAAAAAACE/AG-nIDKCFL8/s400/diana.jpg" alt="" id="BLOGGER_PHOTO_ID_5294260886626364674" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;¿Cómo podrías conseguir 50 puntos tirando a la diana de la figura la menor cantidad posible de dardos?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2580129926531838963?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2580129926531838963/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2580129926531838963' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2580129926531838963'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2580129926531838963'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/tira-la-diana.html' title='TIRA A LA DIANA'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_IdKVSMTg8EI/SXj-Oeeb7QI/AAAAAAAAACE/AG-nIDKCFL8/s72-c/diana.jpg' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2876014344719537413</id><published>2009-01-20T13:10:00.000-08:00</published><updated>2009-01-20T13:19:07.311-08:00</updated><title type='text'>FOTOCOPIAS Y PIPAS</title><content type='html'>En una papelería hay un cartel que dice:&lt;br /&gt;&lt;br /&gt;&lt;div style="text-align: center;"&gt;&lt;span style="font-style: italic;"&gt;"Fotocopias a 20 céntimos; desde 75 fotocopias en adelante, todas a 15 céntimos."&lt;br /&gt;&lt;/span&gt;&lt;div style="text-align: left;"&gt;&lt;span style="font-style: italic;"&gt;&lt;br /&gt;&lt;/span&gt;Un amigo mi0 dice que &lt;span style="font-style: italic;"&gt;necesita fotocopiar un trabajo de 61 páginas, pero que no puede porque solo tiene 11'80 €. Yo le respondo que si, y que además se va a poder comprar una bolsa de pipas.&lt;br /&gt;&lt;br /&gt;¿Cuál es el precio de la bolsa de pipas?&lt;br /&gt;&lt;/span&gt;&lt;span style="font-style: italic;"&gt;&lt;/span&gt;&lt;/div&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2876014344719537413?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2876014344719537413/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2876014344719537413' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2876014344719537413'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2876014344719537413'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/fotocopias-y-pipas.html' title='FOTOCOPIAS Y PIPAS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2740312721032910463</id><published>2009-01-20T13:04:00.000-08:00</published><updated>2009-01-20T13:05:14.668-08:00</updated><title type='text'>TIC-TAC</title><content type='html'>¿Cuántas veces a lo largo de un día las agujas del reloj forman un ángulo recto?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2740312721032910463?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2740312721032910463/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2740312721032910463' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2740312721032910463'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2740312721032910463'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/tic-tac.html' title='TIC-TAC'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-1200457134101142789</id><published>2009-01-17T03:04:00.000-08:00</published><updated>2009-01-17T03:07:06.177-08:00</updated><title type='text'>LA CESTA DE HUEVOS</title><content type='html'>Una cesta tiene una cantidad de huevos que se duplica mágicamente cada minuto. Dentro de una hora estará completamtene llena,  ¿cuanto tiempo tiene que pasar para que se complete hasta su mitad?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-1200457134101142789?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/1200457134101142789/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=1200457134101142789' title='2 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1200457134101142789'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1200457134101142789'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/la-cesta-de-huevos.html' title='LA CESTA DE HUEVOS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-7489135290996473694</id><published>2009-01-14T06:56:00.000-08:00</published><updated>2009-01-14T07:13:05.354-08:00</updated><title type='text'>EL TREN</title><content type='html'>&lt;div style="text-align: center;"&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_IdKVSMTg8EI/SW4A9Fxx3QI/AAAAAAAAAB8/SQlRn1yAjEQ/s1600-h/trenes.jpg"&gt;&lt;img style="cursor: pointer; width: 400px; height: 158px;" src="http://2.bp.blogspot.com/_IdKVSMTg8EI/SW4A9Fxx3QI/AAAAAAAAAB8/SQlRn1yAjEQ/s400/trenes.jpg" alt="" id="BLOGGER_PHOTO_ID_5291167661729897730" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;/div&gt;Dos ferrocarriles se encuentran frente a frente en  una vía. El tren de  la  izquierda tiene 1 vagón y  el de  la  derecha 2. Sólo disponen para maniobrar de  una pequeña vía lateral en la  que  cabe o  una locomotora o  un vagón. Los vagones se pueden enganchar por los dos lados y  las locomotoras sólo los pueden enganchar estirando. ¿Cómo podrán cruzarse los trenes y  continuar su camino?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-7489135290996473694?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/7489135290996473694/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=7489135290996473694' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/7489135290996473694'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/7489135290996473694'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/el-tren.html' title='EL TREN'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_IdKVSMTg8EI/SW4A9Fxx3QI/AAAAAAAAAB8/SQlRn1yAjEQ/s72-c/trenes.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-7497755760259722244</id><published>2009-01-11T03:35:00.000-08:00</published><updated>2009-01-11T04:08:44.823-08:00</updated><title type='text'>CUBO TALLADO</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_IdKVSMTg8EI/SWnhQYwUxUI/AAAAAAAAABs/577jBghP7v8/s1600-h/Cubo_tallado.jpg"&gt;&lt;img style="cursor: pointer; width: 400px; height: 220px;" src="http://1.bp.blogspot.com/_IdKVSMTg8EI/SWnhQYwUxUI/AAAAAAAAABs/577jBghP7v8/s400/Cubo_tallado.jpg" alt="" id="BLOGGER_PHOTO_ID_5290006908962653506" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;En un cubo de 4 centímetros de arista cortamos las tres que concurren en un vértice de forma que la sección sea un triángulo equilátero. Esta operación la repetimos en el resto de vértices, del tal modo que el cuerpo que nos quede tenga todas sus aristas iguales, es decir, esté formado por ocho triángulos equiláteros y por seis hexágonos regulares cuyos lados tengan todos la misma longitud.&lt;br /&gt;&lt;br /&gt;¿A qué distancia del vértice del cubo hemos de cortar la arista para obtener este nuevo cuerpo?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-7497755760259722244?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/7497755760259722244/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=7497755760259722244' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/7497755760259722244'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/7497755760259722244'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/cubo-tallado.html' title='CUBO TALLADO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_IdKVSMTg8EI/SWnhQYwUxUI/AAAAAAAAABs/577jBghP7v8/s72-c/Cubo_tallado.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6621396548611176423</id><published>2009-01-10T03:54:00.000-08:00</published><updated>2009-01-10T04:10:40.164-08:00</updated><title type='text'>MATEMAGIA</title><content type='html'>Escribe un número de tres cifras distintas, el que tu quieras y realiza las operaciones siguientes:&lt;br /&gt;&lt;ul&gt;&lt;li&gt;Debajo de él escribir el mismo número pero con sus cifras colocadas en orden inverso.&lt;/li&gt;&lt;li&gt;Realizar la resta de dichos números, el mayor menos el menor.&lt;/li&gt;&lt;li&gt;Volver a escribir debajo el mismo número obtenido de la resta, pero con las cifras colocadas de nuevo en orden inverso.&lt;/li&gt;&lt;li&gt;Sumar estos dos números.&lt;/li&gt;&lt;/ul&gt;¿Verdad que el resultado es 1089? Explica por qué.&lt;br /&gt;¿Que ocurre si las cifras del número elegido no son distintas?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6621396548611176423?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6621396548611176423/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6621396548611176423' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6621396548611176423'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6621396548611176423'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/matemagia.html' title='MATEMAGIA'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6159515106812857401</id><published>2009-01-07T14:05:00.000-08:00</published><updated>2009-01-07T14:08:16.959-08:00</updated><title type='text'>CICLISTA PUNTUAL</title><content type='html'>Un ciclista va pedaleando tranquilamente a  10 km/h. "He de  ir más rápido - piensa-. A  esta velocidad llegaría con una hora de  retraso". Decide ir a  15 km/h, pero, se da cuenta de que con esta velocidad llegará con una hora de adelanto.&lt;br /&gt;&lt;br /&gt;¿A qué velocidad debe marchar si quiere llegar a la cita a la hora en punto?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6159515106812857401?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6159515106812857401/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6159515106812857401' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6159515106812857401'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6159515106812857401'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/ciclista-puntual.html' title='CICLISTA PUNTUAL'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-355390694774197253</id><published>2009-01-05T05:31:00.000-08:00</published><updated>2009-01-05T05:32:43.840-08:00</updated><title type='text'>EL TELÉFONO DE PILI</title><content type='html'>Ana recuerda el teléfono de su prima Pili (de seis cifras) porque si le pone el 1 del comienzo al final y deja el resto de números en el mismo orden, el número queda automáticamente multiplicado por 3.&lt;br /&gt;&lt;br /&gt;¿Cuál es el número de Pili?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-355390694774197253?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/355390694774197253/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=355390694774197253' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/355390694774197253'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/355390694774197253'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/el-telfono-de-pili.html' title='EL TELÉFONO DE PILI'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4093745551506856855</id><published>2009-01-03T11:58:00.000-08:00</published><updated>2009-01-03T12:02:00.366-08:00</updated><title type='text'>UN TRAPECIO CON PROBLEMAS</title><content type='html'>En un trapecio las bases miden 44 y 16 cm. y los otros dos lados, 17 y 25 cm.&lt;br /&gt;&lt;br /&gt;¿Cuál será su superficie?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4093745551506856855?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4093745551506856855/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4093745551506856855' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4093745551506856855'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4093745551506856855'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/un-trapecio-con-problemas.html' title='UN TRAPECIO CON PROBLEMAS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-1239573089875373774</id><published>2009-01-01T14:56:00.000-08:00</published><updated>2009-01-01T14:57:51.694-08:00</updated><title type='text'>VELOCIDAD MEDIA</title><content type='html'>Un coche realiza el trayecto de ida de un viaje a 60 Km/h y regresa por el mismo camino a 40 km/h, ¿cuál fue la velocidad media del viaje?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-1239573089875373774?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/1239573089875373774/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=1239573089875373774' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1239573089875373774'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/1239573089875373774'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/velocidad-media.html' title='VELOCIDAD MEDIA'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2189662517874579905</id><published>2009-01-01T14:10:00.000-08:00</published><updated>2009-01-01T14:48:23.556-08:00</updated><title type='text'>EL RECONOCIMIENTO</title><content type='html'>Cuatro hombres - Alejandro, Benigno, Cosme y Dositeo - están situados en fila y uno de los hombres es a la vez rubio y elegante y no tiene cicatrices:&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Solo dos de ellos tienen cicatrices.&lt;/li&gt;&lt;li&gt;Los dos hombres que no son rubios están situados al lado de Alejandro.&lt;/li&gt;&lt;li&gt;Benigno es el único que se encuentra junto a un hombre elegante.&lt;/li&gt;&lt;li&gt;Cosme es el único que no se encuentra junto a un hombre que tiene cicatrices.&lt;/li&gt;&lt;/ol&gt;¿Quién es el hombre rubio, elegante y sin cicatrices?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2189662517874579905?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2189662517874579905/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2189662517874579905' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2189662517874579905'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2189662517874579905'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2009/01/el-reconocimiento.html' title='EL RECONOCIMIENTO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-2360365523593622849</id><published>2008-12-27T11:26:00.000-08:00</published><updated>2008-12-27T11:27:35.177-08:00</updated><title type='text'>BALONCESTO</title><content type='html'>Si una pelota de baloncesto pesa 1/2 kilo más la mitad de su propio peso, ¿cuánto pesa?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-2360365523593622849?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/2360365523593622849/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=2360365523593622849' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2360365523593622849'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/2360365523593622849'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/baloncesto.html' title='BALONCESTO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-8989234291767116692</id><published>2008-12-26T02:57:00.000-08:00</published><updated>2008-12-26T03:09:22.881-08:00</updated><title type='text'>1999</title><content type='html'>&lt;span style="font-size:-1;"&gt;&lt;/span&gt;El último año del siglo XX tuvo algo de especial... existen valores, a y b, tales que 1999=a² - b². Encuentra tu el valor de a² + b².&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-8989234291767116692?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/8989234291767116692/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=8989234291767116692' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8989234291767116692'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/8989234291767116692'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/1999.html' title='1999'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6336903175208539692</id><published>2008-12-26T02:38:00.000-08:00</published><updated>2008-12-26T02:46:28.513-08:00</updated><title type='text'>TRIÁNGULO DE DISCOS</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_IdKVSMTg8EI/SVS1_BpwffI/AAAAAAAAABU/EMYeBQfnpOA/s1600-h/triang_bolas.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 177px;" src="http://3.bp.blogspot.com/_IdKVSMTg8EI/SVS1_BpwffI/AAAAAAAAABU/EMYeBQfnpOA/s200/triang_bolas.jpg" alt="" id="BLOGGER_PHOTO_ID_5284048357192400370" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Colocamos 15 discos según el diagrama de la figura. Sabiendo que el radio de cada disco es de 2 cm. ¿Qué longitud tiene el perímetro exterior de la figura?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6336903175208539692?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6336903175208539692/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6336903175208539692' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6336903175208539692'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6336903175208539692'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/tringulo-de-discos.html' title='TRIÁNGULO DE DISCOS'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_IdKVSMTg8EI/SVS1_BpwffI/AAAAAAAAABU/EMYeBQfnpOA/s72-c/triang_bolas.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-3081160621141203164</id><published>2008-12-21T14:55:00.000-08:00</published><updated>2008-12-21T15:00:10.389-08:00</updated><title type='text'>UN NÚMERO ESCONDIDO</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_IdKVSMTg8EI/SU7KcX-FilI/AAAAAAAAABE/6iDX5ELVR00/s1600-h/numeros.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 91px;" src="http://3.bp.blogspot.com/_IdKVSMTg8EI/SU7KcX-FilI/AAAAAAAAABE/6iDX5ELVR00/s200/numeros.jpg" alt="" id="BLOGGER_PHOTO_ID_5282382001771743826" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;¿Qué número es el que completa la tabla?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-3081160621141203164?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/3081160621141203164/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=3081160621141203164' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/3081160621141203164'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/3081160621141203164'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/un-nmero-escondido.html' title='UN NÚMERO ESCONDIDO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_IdKVSMTg8EI/SU7KcX-FilI/AAAAAAAAABE/6iDX5ELVR00/s72-c/numeros.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-5253045316946353701</id><published>2008-12-21T14:51:00.000-08:00</published><updated>2008-12-21T14:54:34.948-08:00</updated><title type='text'>CHULETAS A LA PLANCHA</title><content type='html'>Queremos asar a la plancha tres chuletas. Solo caben dos cada vez en la plancha y cada tanda tarda quince minutos en hacerse por cada lado. ¿Cuál es el mínimo tiempo que se puede tardar en hacer las tres chuletas?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-5253045316946353701?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/5253045316946353701/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=5253045316946353701' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5253045316946353701'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/5253045316946353701'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/chuletas-la-plancha.html' title='CHULETAS A LA PLANCHA'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-7132197055332729770</id><published>2008-12-17T04:58:00.000-08:00</published><updated>2008-12-17T05:09:43.090-08:00</updated><title type='text'>LA HUERTA DEL GRANJERO</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_IdKVSMTg8EI/SUj6DIFEPGI/AAAAAAAAAA8/Fi0oL89jc3U/s1600-h/GRANJERO.JPG"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 199px;" src="http://3.bp.blogspot.com/_IdKVSMTg8EI/SUj6DIFEPGI/AAAAAAAAAA8/Fi0oL89jc3U/s200/GRANJERO.JPG" alt="" id="BLOGGER_PHOTO_ID_5280745494707190882" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Un granjero tiene un huerta en forma de cuadrado, el lado del cuadrado mide 8 metros. Ha dividido su interior en tres zonas, tal y como se muestra en la figura. Sabiendo que el punto E coincide con el punto medio del segmento AD y que CF es perpendicular al segmento BE. ¿Cuál es el área del cuadrilátero CDEF?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-7132197055332729770?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/7132197055332729770/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=7132197055332729770' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/7132197055332729770'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/7132197055332729770'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/la-huerta-del-granjero.html' title='LA HUERTA DEL GRANJERO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_IdKVSMTg8EI/SUj6DIFEPGI/AAAAAAAAAA8/Fi0oL89jc3U/s72-c/GRANJERO.JPG' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4145306423893066957</id><published>2008-12-15T00:59:00.000-08:00</published><updated>2008-12-15T01:06:53.154-08:00</updated><title type='text'>UNA SALIDA CON DOS PUERTAS.</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_IdKVSMTg8EI/SUYeHY_wIWI/AAAAAAAAAA0/riua_0PWHJg/s1600-h/puertas.jpg"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 118px;" src="http://2.bp.blogspot.com/_IdKVSMTg8EI/SUYeHY_wIWI/AAAAAAAAAA0/riua_0PWHJg/s200/puertas.jpg" alt="" id="BLOGGER_PHOTO_ID_5279940725456249186" border="0" /&gt;&lt;/a&gt;El esquema representa uno de los controles de salida de unos grandes almacenes, el cual desemboca en dos puertas A y B. La gente accede a ellas aleatoriamente. Si en un día han accedido a ese control 750 personas,  ¿cuántas habrán salido por cada una de las puertas? &lt;span style="font-size:85%;"&gt;&lt;/span&gt;&lt;p align="justify"&gt;  &lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4145306423893066957?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4145306423893066957/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4145306423893066957' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4145306423893066957'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4145306423893066957'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/una-salida-con-dos-puertas.html' title='UNA SALIDA CON DOS PUERTAS.'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_IdKVSMTg8EI/SUYeHY_wIWI/AAAAAAAAAA0/riua_0PWHJg/s72-c/puertas.jpg' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6955490948142481316</id><published>2008-12-14T09:41:00.000-08:00</published><updated>2008-12-14T09:52:28.532-08:00</updated><title type='text'>LAS PALOMAS Y EL GAVILÁN</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_IdKVSMTg8EI/SUVHzjxZ02I/AAAAAAAAAAk/XpZ-XqqMqCY/s1600-h/PALOMA_PAZ.JPG"&gt;&lt;img style="margin: 0pt 10px 10px 0pt; float: left; cursor: pointer; width: 160px; height: 126px;" src="http://3.bp.blogspot.com/_IdKVSMTg8EI/SUVHzjxZ02I/AAAAAAAAAAk/XpZ-XqqMqCY/s200/PALOMA_PAZ.JPG" alt="" id="BLOGGER_PHOTO_ID_5279705089263129442" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Un gavilán se cruza con lo que parece un centenar de palomas, pero una le dice: “No somos cien. Si fuésemos las que somos, más tantas como las que somos, más la mitad de las que somos, más la mitad de la mitad de las que somos, en ese caso, contigo, gavilán, seríamos 100”.&lt;br /&gt;&lt;br /&gt;¿Cuántas palomas volaban en la bandada?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6955490948142481316?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6955490948142481316/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6955490948142481316' title='1 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6955490948142481316'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6955490948142481316'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/las-palomas-y-el-gaviln.html' title='LAS PALOMAS Y EL GAVILÁN'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_IdKVSMTg8EI/SUVHzjxZ02I/AAAAAAAAAAk/XpZ-XqqMqCY/s72-c/PALOMA_PAZ.JPG' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-6716451311765287501</id><published>2008-12-11T02:53:00.000-08:00</published><updated>2008-12-11T02:55:40.634-08:00</updated><title type='text'>LAS PÁGINAS DE UN LIBRO</title><content type='html'>Han hecho falta 4221 caracteres para numerar las páginas de un libro.&lt;br /&gt;&lt;br /&gt;¿Cuántas páginas tiene?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-6716451311765287501?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/6716451311765287501/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=6716451311765287501' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6716451311765287501'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/6716451311765287501'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/las-pginas-de-un-libro.html' title='LAS PÁGINAS DE UN LIBRO'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5751395376029001098.post-4715080035957119497</id><published>2008-12-09T01:52:00.000-08:00</published><updated>2008-12-09T01:55:15.553-08:00</updated><title type='text'>LA PARCELA</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_IdKVSMTg8EI/ST5AdUEo9NI/AAAAAAAAAAc/Y_ZkAoEgygM/s1600-h/prob01.JPG"&gt;&lt;img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 200px; height: 194px;" src="http://2.bp.blogspot.com/_IdKVSMTg8EI/ST5AdUEo9NI/AAAAAAAAAAc/Y_ZkAoEgygM/s200/prob01.JPG" alt="" id="BLOGGER_PHOTO_ID_5277726685673354450" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Maria es propietaria de un terrenito con la forma que se ve en la figura. Este terreno posee la propiedad de que si medimos su perímetro en km y su área en km², las dos medidas están representadas por el mismo número.&lt;br /&gt;&lt;br /&gt;¿Cuál es el perímetro del terrenito?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5751395376029001098-4715080035957119497?l=abueno34.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://abueno34.blogspot.com/feeds/4715080035957119497/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=5751395376029001098&amp;postID=4715080035957119497' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4715080035957119497'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5751395376029001098/posts/default/4715080035957119497'/><link rel='alternate' type='text/html' href='http://abueno34.blogspot.com/2008/12/la-parcela.html' title='LA PARCELA'/><author><name>Antonio Bueno</name><uri>http://www.blogger.com/profile/03837507328919284522</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_IdKVSMTg8EI/ST5AdUEo9NI/AAAAAAAAAAc/Y_ZkAoEgygM/s72-c/prob01.JPG' height='72' width='72'/><thr:total>0</thr:total></entry></feed>
